标题：一套不是很好用的c语言UTF8读写函数
出处：Felix021
时间：Thu, 30 Sep 2010 14:08:08 +0000
作者：felix021
地址：https://www.felix021.com/blog/read.php?1936

内容：
看了下百度百科对UTF-8的说明，随手写的，基本能用。

比较诡异的是本来UTF8getchar想用strncpy的，但是这个函数有坑....

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <assert.h>

#define alloc(type, size) ((type *)malloc(sizeof(type) * size))

struct UTF8char
{
    unsigned short length;
    char data[7];
};

unsigned UTF8getcharlen(const char *s)
{
    unsigned char t = (unsigned char) s[0];
    if (t < 0x80) //0xxx xxxx
        return 1;
    else if (t < 0xe0) //110x xxxx
        return 2;
    else if (t < 0xf0) //1110 xxxx
        return 3;
    else if (t < 0xf8) //1111 0xxx
        return 4;
    else if (t < 0xfc) //1111 10xx
        return 5;
    else if (t < 0xfe) //1111 110x
        return 6;
    else //0xff
        return 1;
}

int UTF8getchar(UTF8char *c, const char *s)
{
    int i;
    c->length = UTF8getcharlen(s);
    for (i = 0; i < c->length && s[i] != 0; i++)
        c->data[i] = s[i];
    c->data[i] = 0;
    return (i == c->length);
}

int UTF8cmp(const UTF8char *c, const char *s)
{
    return strncmp(c->data, s, c->length);
}

int main()
{
    char linebuf[4096];
    UTF8char c;

    scanf("%s", linebuf);

    int reti = UTF8getchar(&c, linebuf);
    assert(reti != 0);

    printf("%d %s\n", c.length, c.data);
    return 0;
}



Generated by Bo-blog 2.1.0